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Test
Math
Domain
Algebra
Skill
Linear inequalities in one or two variables
Difficulty
Hard
ID: ee7b1de1
Modded SAT Question Bank by Abdullah Mallik

A small business owner budgets $2,200 to purchase candles. The owner must purchase a minimum of 200 candles to maintain the discounted pricing. If the owner pays $4.90 per candle to purchase small candles and $11.60 per candle to purchase large candles, what is the maximum number of large candles the owner can purchase to stay within the budget and maintain the discounted pricing?


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Correct Answer: 182
Rationale

The correct answer is 182. Let s represent the number of small candles the owner can purchase, and let l represent the number of large candles the owner can purchase. It’s given that the owner pays $4.90 per candle to purchase small candles and $11.60 per candle to purchase large candles. Therefore, the owner pays 4.90s dollars for s small candles and 11.60l dollars for l large candles, which means the owner pays a total of 4.90s+11.60l dollars to purchase candles. It’s given that the owner budgets $2,200 to purchase candles. Therefore, 4.90s+11.60l≀2,200. It’s also given that the owner must purchase a minimum of 200 candles. Therefore, s+lβ‰₯200. The inequalities 4.90s+11.60l≀2,200 and s+lβ‰₯200 can be combined into one compound inequality by rewriting the second inequality so that its left-hand side is equivalent to the left-hand side of the first inequality. Subtracting l from both sides of the inequality s+lβ‰₯200 yields sβ‰₯200-l. Multiplying both sides of this inequality by 4.90 yields 4.90sβ‰₯4.90200-l, or 4.90sβ‰₯980-4.90l. Adding 11.60l to both sides of this inequality yields 4.90s+11.60lβ‰₯980-4.90l+11.60l, or 4.90s+11.60lβ‰₯980+6.70l. This inequality can be combined with the inequality 4.90s+11.60l≀2,200, which yields the compound inequality 980+6.70l≀4.90s+11.60l≀2,200. It follows that 980+6.70l≀2,200. Subtracting 980 from both sides of this inequality yields 6.70l≀2,200. Dividing both sides of this inequality by 6.70 yields approximately l≀182.09. Since the number of large candles the owner purchases must be a whole number, the maximum number of large candles the owner can purchase is the largest whole number less than 182.09, which is 182.

Question Difficulty: Hard
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