Question #2d0e13a6 - SAT Suite Question Bank

ID: 2d0e13a6

Modded SAT Question Bank by Abdullah Mallik

Line $k$ is defined by $y = \frac{1}{4} x + 1$ . Line $j$ is parallel to line $k$ in the xy-plane. What is the slope of $j$ ?

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Correct Answer: .25, 1/4

Rationale

The correct answer is $\frac{1}{4}$ . It's given that line $k$ is defined by $y = \frac{1}{4} x + 1$ . It's also given that line $j$ is parallel to line $k$ in the xy-plane. A line in the xy-plane represented by an equation in slope-intercept form $y = m x + b$ has a slope of $m$ and a y-intercept of $left parenthesis 0 comma b right parenthesis$ . Therefore, the slope of line $k$ is $\frac{1}{4}$ . Since parallel lines have equal slopes, the slope of line $j$ is $\frac{1}{4}$ . Note that 1/4 and .25 are examples of ways to enter a correct answer.

Question Difficulty: Easy