Question #c81b6c57 - SAT Suite Question Bank

ID: c81b6c57

Modded SAT Question Bank by Abdullah Mallik

In the expression $\text{[math]}$ , p is a constant. This expression is equivalent to the expression $6 x squared minus 155 x plus 24$ . What is the value of p ?

$negative 3$
$7$
$13$
$155$

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Correct Answer: B

Rationale

Choice B is correct. Using the distributive property, the first given expression can be rewritten as 6x² + 3px + 24 – 16px – 64x + 24, and then rewritten as 6x² + (3p – 16p – 64)x + 24. Since the expression 6x² + (3p – 16p – 64)x + 24 is equivalent to 6x² – 155x + 24, the coefficients of the x terms from each expression are equivalent to each other; thus 3p – 16p – 64 = –155. Combining like terms gives –13p – 64 = –155. Adding 64 to both sides of the equation gives –13p = –71. Dividing both sides of the equation by –13 yields p = 7.

Choice A is incorrect. If p = –3, then the first expression would be equivalent to 6x² – 25x + 24. Choice C is incorrect. If p = 13, then the first expression would be equivalent to 6x² – 233x + 24. Choice D is incorrect. If p = 155, then the first expression would be equivalent to 6x² – 2,079x + 24.

Question Difficulty: Hard