Question #29ed5d39 - SAT Suite Question Bank

ID: 29ed5d39

Modded SAT Question Bank by Abdullah Mallik

$p = 20 + \frac{16}{n}$

The given equation relates the numbers $p$ and $n$ , where $n$ is not equal to $0$ and $p greater than 20$ . Which equation correctly expresses $n$ in terms of $p$ ?

$n = \frac{p - 20}{16}$
$n = \frac{p}{16} + 20$
$n = \frac{p}{16} - 20$
$n = \frac{16}{p - 20}$

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Correct Answer: D

Rationale

Choice D is correct. To express $n$ in terms of $p$ , the given equation must be solved for $n$ . Subtracting $9$ from both sides of the given equation yields $p - 9 = \frac{14}{n}$ . Since $n$ is not equal to $0$ , multiplying both sides of this equation by $n$ yields $(p - 9) (n) = 14$ . It's given that $p greater than 9$ , which means $p minus 9$ is not equal to $0$ . Therefore, dividing both sides of $(p - 9) (n) = 14$ by $left parenthesis p minus 9 right parenthesis$ yields $\frac{(p - 9) (n)}{p - 9} = \frac{14}{p - 9}$ , or $n = \frac{14}{p - 9}$ .

Choice A is incorrect and may result from conceptual or calculation errors.

Choice B is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect and may result from conceptual or calculation errors.

Question Difficulty: Medium