Question #1e003284 - SAT Suite Question Bank

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Modded SAT Question Bank by Abdullah Mallik

$x equals 49$

$y = \sqrt{x} + 9$

The graphs of the given equations intersect at the point $(x, y)$ in the xy-plane. What is the value of $y$ ?

$16$
$40$
$81$
$130$

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Correct Answer: A

Rationale

Choice A is correct. It's given that the graphs of the given equations intersect at the point $(x, y)$ in the xy-plane. It follows that $(x, y)$ represents a solution to the system consisting of the given equations. The first equation given is $x equals 49$ . Substituting $49$ for $x$ in the second equation given, $y = \sqrt{x} + 9$ , yields $y = \sqrt{49} + 9$ , which is equivalent to $y = 7 + 9$ , or $y equals 16$ . It follows that the graphs of the given equations intersect at the point $left parenthesis 49 comma 16 right parenthesis$ . Therefore, the value of $y$ is $16$ .

Choice B is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect and may result from conceptual or calculation errors.

Choice D is incorrect and may result from conceptual or calculation errors.

Question Difficulty:

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