Question #4236c5a3 - SAT Suite Question Bank

ID: 4236c5a3

Modded SAT Question Bank by Abdullah Mallik

If $open parenthesis, x plus 5, close parenthesis, squared, equals 4$ , which of the following is a possible value of x ?

1
$negative 1$
$negative 2$
$negative 3$

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Correct Answer: D

Rationale

Choice D is correct. If $open parenthesis, x plus 5, close parenthesis, squared, equals 4$ , then taking the square root of each side of the equation gives $x plus 5, equals 2$ or $x plus 5, equals negative 2$ . Solving these equations for x gives $x equals negative 3$ or $x equals negative 7$ . Of these, $negative 3$ is the only solution given as a choice.

Choice A is incorrect and may result from solving the equation $x plus 5, equals 4$ and making a sign error. Choice B is incorrect and may result from solving the equation $x plus 5, equals 4$ . Choice C is incorrect and may result from finding a possible value of $x plus 5$ .

Question Difficulty: Easy