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Test
Math
Domain
Geometry and Trigonometry
Skill
Circles
Difficulty
Hard
ID: 24cec8d1
Modded SAT Question Bank by Abdullah Mallik

A circle has center O, and points R and S lie on the circle. In triangle ORS, the measure of ROS is 88°. What is the measure of RSO, in degrees? (Disregard the degree symbol when entering your answer.)


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Correct Answer: 46
Rationale

The correct answer is 46. It's given that O is the center of a circle and that points R and S lie on the circle. Therefore, OR¯ and OS¯ are radii of the circle. It follows that OR=OS. If two sides of a triangle are congruent, then the angles opposite them are congruent. It follows that the angles RSO and ORS, which are across from the sides of equal length, are congruent. Let x° represent the measure of RSO. It follows that the measure of ORS is also x°. It's given that the measure of ROS is 88°. Because the sum of the measures of the interior angles of a triangle is 180°, the equation x°+x°+88°=180°, or 2x+88=180, can be used to find the measure of RSO. Subtracting 88 from both sides of this equation yields 2x=92. Dividing both sides of this equation by 2 yields x=46. Therefore, the measure of RSO, in degrees, is 46.

Question Difficulty: Hard
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