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Test
Math
Domain
Advanced Math
Skill
Nonlinear functions
Difficulty
Medium
ID: 7e5a3640
Modded SAT Question Bank by Abdullah Mallik

Bacteria are growing in a liquid growth medium. There were 300,000 cells per milliliter during an initial observation. The number of cells per milliliter doubles every 3 hours. How many cells per milliliter will there be 15 hours after the initial observation?

  1. 1,500,000

  2. 2,400,000

  3. 4,500,000

  4. 9,600,000


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Correct Answer: D
Rationale

Choice D is correct. Let y represent the number of cells per milliliter x hours after the initial observation. Since the number of cells per milliliter doubles every 3 hours, the relationship between x and y can be represented by an exponential equation of the form y=abxk, where a is the number of cells per milliliter during the initial observation and the number of cells per milliliter increases by a factor of b every k hours. It’s given that there were 300,000 cells per milliliter during the initial observation. Therefore, a=300,000. It’s also given that the number of cells per milliliter doubles, or increases by a factor of 2, every 3 hours. Therefore, b=2 and k=3. Substituting 300,000 for a, 2 for b, and 3 for k in the equation y=abxk yields y=300,0002x3. The number of cells per milliliter there will be 15 hours after the initial observation is the value of y in this equation when x=15. Substituting 15 for x in the equation y=300,0002x3 yields y=300,0002153, or y=300,00025. This is equivalent to y=300,00032, or y=9,600,000. Therefore, 15 hours after the initial observation, there will be 9,600,000 cells per milliliter.

Choice A is incorrect and may result from conceptual or calculation errors.

Choice B is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect and may result from conceptual or calculation errors.

Question Difficulty: Medium
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