Question #6989c80a - SAT Suite Question Bank

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Modded SAT Question Bank by Abdullah Mallik

$F (x) = \frac{9}{5} (x - 273.15) + 32$

The function $F$ gives the temperature, in degrees Fahrenheit, that corresponds to a temperature of $x$ kelvins. If a temperature increased by $2.10$ kelvins, by how much did the temperature increase, in degrees Fahrenheit?

$3.78$
$35.78$
$487.89$
$519.89$

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Correct Answer: A

Rationale

Choice A is correct. It’s given that the function $F (x) = \frac{9}{5} (x - 273.15) + 32$ gives the temperature, in degrees Fahrenheit, that corresponds to a temperature of $x$ kelvins. A temperature that increased by $2.10$ kelvins means that the value of $x$ increased by $2.10$ kelvins. It follows that an increase in $x$ by $2.10$ increases $F (x)$ by $nine fifths left parenthesis 2.10 right parenthesis$ , or $3.78$ . Therefore, if a temperature increased by $2.10$ kelvins, the temperature increased by $3.78$ degrees Fahrenheit.

Choice B is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect and may result from conceptual or calculation errors.

Choice D is incorrect and may result from conceptual or calculation errors.

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